Posted by **Chelsea** on Wednesday, February 1, 2012 at 4:09pm.

Solve the inequality by first rewriting it as an equivalent inequality without absolute value bars. Express solution set using interval notation.

| x+3 | +8 is less than or equal to 14

Thanks so much for helping me!

- Math -
**Henry**, Friday, February 3, 2012 at 4:09pm
|x+3| + 8 <= 14,

|x+3| <= 6,

+-(x+3)<= 6,

+(x+3) <= 6,

x+3 >= 6,

X <= 6-3,

X <= 3.

-(x+3) <= 6,

-x - 3 <= 6,

-x <= 6+3,

-x <= 9,

X >= -9.

Solution set: -9 =< X <= 3.

Intrval notation: [-9,3].

## Answer This Question

## Related Questions

- Algebra II - I need some help with some problems as well as need some checked. ...
- precalculus - solve the inequality algebraically. write the solution in interval...
- Solve Inequality - Solve the inequality. Express your solution using interval ...
- Math inequalitites - Hi, I need some help with some inequalitites. Thanks!! Use ...
- algebra 1 - Inequality 3 | 2x-2 | +16<58 •simplify as much as possible ...
- algebra - solve the inequality. Express the solution using interval notation and...
- math/algebra - Solve the polynomial inequality and graph the solution set on a ...
- Algebra - Right now we are learning about absolute value inequalities. I have to...
- math - can some one solve this Ex 1: -2x+7>22 -2x+7-7>22-7 -2x>15 -2x...
- algebra - Solve the polynomial inequality and graph the solution set on a real ...

More Related Questions