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April 19, 2014

April 19, 2014

Posted by **Matt** on Wednesday, February 1, 2012 at 1:38pm.

- Math: Algebra -
**Steve**, Wednesday, February 1, 2012 at 5:41pmthe distance is the same

Let s be his uphill speed

d/s = 6

d/(s+2.5) = .75

6s = .75(s+2.5)

6s = 3s/4 + 15/8

48s = 6s + 15

42s = 15

s = 15/42 = 5/14

So, he can go up at 5/14 mph and come down at 20/7 mph

6*5/14 = 30/14

3/4 * 20/7 = 60/28 = 30/14

Looks like the hill is 15/7 miles long.

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