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April 18, 2014

April 18, 2014

Posted by **bbadger** on Wednesday, February 1, 2012 at 12:48pm.

- physics -
**bobpursley**, Wednesday, February 1, 2012 at 1:18pmEasy way: relative motion

relative initial speed: (91-83)km/hr=8km/hr= 2.2222 m/s

distancerelative=virelative*time+1/2 a t^2

52=2.22*16+1/2 a (256)

solve for a.

Harder method:

find the distance the slow car goes in 16 seconds: (velocity*time)

find the distance the fast car must go (above+ 52)

then

that distance=Vi*16 + 1/2 *256 a

check my thinkikng.

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