Math
posted by Alone3030 .
Given points P(2,1), Q(4, 2), and M(5,3), find coordinates of a point K such that MK is perpendicular to PQ.

The slope of PQ is (2+1)/(42) = 3/6 = 1/2
The slope of any line perpendicular to PQ will thus be 3.
Now you have a point and a slope. The line perpendicular to PQ and passing through M is
(y3)/(x5) = 3