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Posted by on Wednesday, February 1, 2012 at 10:55am.

A capacitor is constructed of two concentric conducting cylindrical shells. The radius of the inner cylindrical shell is 2.35 10-3 m, and that of the outer shell is 2.49 10-3 m. When the cylinders carry equal and opposite charges of magnitude 1.61 10-10 C, the electric field between the plates has an average magnitude of 3.80 104 V/m and is directed radially outward from the inner shell to the outer shell.
Determine the magnitude of the potential difference between the cylindrical shells.
Determine the capacitance of this capacitor.

  • Physics - , Wednesday, February 1, 2012 at 12:08pm

    You will find the formulas that you need here:
    http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capcyl.html

    In this case, the gap is so narrow compared to the radius that you can get very high accuracy by treating it as a planar capacitor with gap 0.14*10^-3 m. Multiply that by the average E-field between the cylindrical plates, to get the potential difference, 5.32 V .

    The capacitance is C = Q/V

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