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March 29, 2015

March 29, 2015

Posted by **mien** on Wednesday, February 1, 2012 at 7:28am.

- trig -
**Reiny**, Wednesday, February 1, 2012 at 11:13amsecØ - tanØsinØ = cosØ

LS (left side)

= 1/cosØ - (sinØ/cosØ)sinØ

= (1 - sin^2 Ø)/cosØ

= cos^2 Ø/cosØ

= cosØ

= RS

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