How many moles of hypochlorous acid are needed to react with 0.621 mol of 9-fluorenol?
please help
The answer is 0.621 mol of hypochlorous acid because there is a 1:1 molar ratio in the balanced chemical equation.
To determine the number of moles of hypochlorous acid needed to react with 0.621 mol of 9-fluorenol, we first need to balance the chemical equation for the reaction between hypochlorous acid (HOCl) and 9-fluorenol.
The balanced chemical equation for the reaction is:
2 HOCl + 9-fluorenol -> 9-fluorenone + 2 HCl + H2O
From the balanced equation, we can see that 2 moles of hypochlorous acid react with 1 mole of 9-fluorenol.
Now, to calculate the number of moles of hypochlorous acid needed, we can use the following conversion:
moles of hypochlorous acid = (moles of 9-fluorenol) * (2 / 1)
Substituting the given value:
moles of hypochlorous acid = 0.621 mol * (2 / 1) = 1.242 mol
Therefore, 1.242 moles of hypochlorous acid are needed to react with 0.621 mol of 9-fluorenol.