Posted by **Betty** on Wednesday, February 1, 2012 at 12:24am.

Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by

.

a) What was the average score when they initially took the test, t = 0? Round your answer to a whole percent, if necessary.

S(t)= 68 - 20 log (t+1), t > 0

- College Algebra -
**Steve**, Wednesday, February 1, 2012 at 5:06pm
what's the problem? Just plug in t=0:

S(0) = 68-20log(1) = 68 - 20(0) = 68

Although, as written, S(0) is not defined, since it is only for t>0, not t=0.

Looks like the scores keep going down and down. Is the problem written correctly?

- College Algebra -
**mike**, Thursday, March 8, 2012 at 3:39pm
WHAT WOULD THE SCORE BE AFTER 4 MONTHS

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