College Algebra
posted by Betty on .
Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by
.
a) What was the average score when they initially took the test, t = 0? Round your answer to a whole percent, if necessary.
S(t)= 68  20 log (t+1), t > 0

what's the problem? Just plug in t=0:
S(0) = 6820log(1) = 68  20(0) = 68
Although, as written, S(0) is not defined, since it is only for t>0, not t=0.
Looks like the scores keep going down and down. Is the problem written correctly? 
WHAT WOULD THE SCORE BE AFTER 4 MONTHS