The wall height, d, of the first story is 11 feet. The center height h of the second story has not yet been determined. Find h such that the second story will have the same cross-sectional area as the first story
To find the height of the second story, h, such that it has the same cross-sectional area as the first story, we first need to determine the cross-sectional area of the first story.
The cross-sectional area of a rectangle is given by the formula A = length × width. In this case, the length of the first story wall is not given, so we'll assume it to be a constant value. Let's denote the length of the first story wall as L.
Given that the height of the first story wall is 11 feet, we can write the equation for the cross-sectional area of the first story as A1 = L × 11.
Now, we need to find the height, h, of the second story wall such that its cross-sectional area is equal to A1. We can use the formula for the cross-sectional area of the second story to set up an equation.
The cross-sectional area of the second story would be A2 = L × h.
Since we want the areas of both stories to be equal, we can set up the following equation:
A1 = A2
L × 11 = L × h
Now, we can solve this equation for h by canceling out the common factor 'L':
11 = h
Therefore, the height of the second story, h, is 11 feet, which is the same as the height of the first story wall.