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Mathematics
Trigonometry
Calculating trigonometric values without a calculator
How can I find the exact value of 4cos(7ð/4)-2sin(ð/3) without using a calculator (show work)?
1 answer
that weird symbol is suppose to be pi (3.14...) I punched in the alt code but it seems after I submitted the question it turned out like this
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How can I find the exact value of 4cos(7ð/4)-2sin(ð/3)?
Top answer:
In a graphic calculator punch in cos(7/4) and should give you the right answer subtract it from
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find the exact value of the following (show your work using exact values)
a) sin^2 45 + cos^2 45 b)2sin^2 45 + cos (2 * 45)
Top answer:
a) We know that sin^2(x) + cos^2(x) = 1 for any angle x. Therefore, sin^2(45) + cos^2(45) = 1. b)
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1. Show that Sin3 Theta - Cos2 Theta = (1 - Sin Theta)(4Sin^2 Theta + 2Sin Theta - 1).
Without using a calculator, show that
Top answer:
To prove that Sin3 Theta - Cos2 Theta = (1 - Sin Theta)(4Sin^2 Theta + 2Sin Theta - 1), we can start
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If f(x)= (4cos^4x+2cos^2x+2sin^2x-x^9-1/2cos4x)^(1/9). Find f(f(2))
Top answer:
To find f(f(2)), we need to first evaluate f(2) and then substitute the result into the function
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2sin(x)cos(x)+cos(x)=0
I'm looking for exact value solutions in [0, 3π] So I need to find general solutions to solve the
Top answer:
when you divide both sides by cos x, you divide by zero when cos x = 0. Not allowed. However your
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Suppose that sin q = − 12/13 and that q is a Quadrant IV angle.
(a) Find the exact value of cos q. Show work. (b) Find the
Top answer:
(a) To find the exact value of cos q, we can use the Pythagorean identity: sin^2 q + cos^2 q = 1.
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Suppose that cos θ = 12/13 and that θ is a Quadrant IV angle.
(a) Find the exact value of sin θ. Show work. (b) Find the exact
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a
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1. Show that Sin3è - Cos2è = (1 - Sinè)(4Sin^2è + 2Sinè - 1).
Without using a calculator, show that è = 18 degrees is an
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I will use x instead of è sin 3x - cos 2x = (1-sinx)(4sin^2 x + 2sinx - 1) RS = 4sin^2 x + 2sinx -
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What am I doing wrong?
Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) =
Top answer:
wouldn't it be easier to solve for 2x then divide it by two? sin2x=2cos2x sin2x/cos2x=2 tan 2x=2
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Sin(2x)=2sin(x)cos(x) find the exact value in radians with 2sin^2(x)+sin^2(x)=0, i really do not get this question or even how
Top answer:
you have a typo. There is no sin(2x) in the equation, and sin^2(x) appears twice. Reread the problem
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