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April 20, 2014

April 20, 2014

Posted by **lisa** on Tuesday, January 31, 2012 at 8:01pm.

- math -
**Reiny**, Tuesday, January 31, 2012 at 8:53pmI know that there are formulas in physics for this type of question, but I am not a physics teacher , so I will use standard Calculus

a = (v2 - v1)/(time2 - time1) = (26-20)/(12-0) = 6/12 = 1/2

since a = 1/2

v = (1/2)t + c

when t = 0, v = 20

20 = c

so v = (1/2)t + 20

then

d = (1/4)t^2 + 20t + k

at t=0 , d = k

at t = 12 , d = (1/4)(144) + 20(12) + k= 276+k

distance covered in that 12 seconds = 276k - k = 276 m

drwls or bobpursley could do it much easier.

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