Posted by **Anonymous** on Tuesday, January 31, 2012 at 7:13pm.

A ball is thrown from a point 1.1 m above the ground. The initial velocity is 20.3 m/s at an angle of 32.0° above the horizontal.

(a) Find the maximum height of the ball above the ground???

(b) Calculate the speed of the ball at the highest point in the trajectory???

- PHYSICS -
**drwls**, Tuesday, January 31, 2012 at 8:13pm
(a) Maximum height H is where

g*H = (Vo*sin32)^2/2

(b) Vo*cos35, which remains constant while the vertical velocity component becomes zero at max height.

- PHYSICS -
**Anonymous**, Tuesday, January 31, 2012 at 8:49pm
What would the Vo be???

0 or 20.3???

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