Posted by **Anonymous** on Tuesday, January 31, 2012 at 7:13pm.

A ball is thrown from a point 1.1 m above the ground. The initial velocity is 20.3 m/s at an angle of 32.0° above the horizontal.

(a) Find the maximum height of the ball above the ground???

(b) Calculate the speed of the ball at the highest point in the trajectory???

- PHYSICS -
**drwls**, Tuesday, January 31, 2012 at 8:13pm
(a) Maximum height H is where

g*H = (Vo*sin32)^2/2

(b) Vo*cos35, which remains constant while the vertical velocity component becomes zero at max height.

- PHYSICS -
**Anonymous**, Tuesday, January 31, 2012 at 8:49pm
What would the Vo be???

0 or 20.3???

## Answer This Question

## Related Questions

- Physics - A ball is thrown from a point 1.0 m above the ground. The initial ...
- physics - A ball is thrown from a point 1.38 m above the ground. The initial ...
- Physics - A ball is thrown from a point 1.38 m above the ground. The initial ...
- Physics - A ball is thrown from a point 1.38 m above the ground. The initial ...
- Physics - A ball is thrown from a point 1.38 m above the ground. The initial ...
- Physics - A ball is thrown from a point 1.1 m above the ground. The initial ...
- PHYSICS - A ball is thrown from a point 1.1 m above the ground. The initial ...
- PHYSICS - A ball is thrown from a point 1.2 m above the ground. The initial ...
- Physics - A 0.2 kg baseball located at the top of a building which is 100 m ...
- Physics - A tennis player hits a ball at ground level, giving it an initial ...

More Related Questions