Posted by Anonymous on Tuesday, January 31, 2012 at 7:13pm.
A ball is thrown from a point 1.1 m above the ground. The initial velocity is 20.3 m/s at an angle of 32.0° above the horizontal.
(a) Find the maximum height of the ball above the ground???
(b) Calculate the speed of the ball at the highest point in the trajectory???

PHYSICS  drwls, Tuesday, January 31, 2012 at 8:13pm
(a) Maximum height H is where
g*H = (Vo*sin32)^2/2
(b) Vo*cos35, which remains constant while the vertical velocity component becomes zero at max height.

PHYSICS  Anonymous, Tuesday, January 31, 2012 at 8:49pm
What would the Vo be???
0 or 20.3???
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