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A ball is thrown from a point 1.1 m above the ground. The initial velocity is 20.3 m/s at an angle of 32.0° above the horizontal.

(a) Find the maximum height of the ball above the ground???

(b) Calculate the speed of the ball at the highest point in the trajectory???

  • PHYSICS - ,

    (a) Maximum height H is where
    g*H = (Vo*sin32)^2/2
    (b) Vo*cos35, which remains constant while the vertical velocity component becomes zero at max height.

  • PHYSICS - ,

    What would the Vo be???

    0 or 20.3???

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