Homework Help: Precalculus

Posted by jake on Tuesday, January 31, 2012 at 7:09pm.

When a projectile leaves a starting point at an angle of elevation of theta with a velocity v, the horizontal distance it travels is determined by:

d=v^2/(32) sin2theta

Where d is measured in feet and v in feet per second.

An outfielder throws the ball at a speed of 75 miles per hour to the catcher who is 200 feet away. At what angle of elevation was the ball thrown?

Precalculus - Reiny, Tuesday, January 31, 2012 at 8:12pm
sub in the values
200 = 75^2/2 sin^2 Ų
400/5625 = sin^2 Ų
sin Ų = √(400/5625) = 20/75 = 1/3
Ų = 19.5°
Precalculus - jake, Tuesday, January 31, 2012 at 8:38pm
The answer says:16.0 or 74.0 degrees :|

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