A motorcycle traveling 91.0 km/hr approaches a car traveling in the same direction at 83.0 km/hr. When the motorcycle is 52.0 m behind the car, the rider accelerates and passes the car 16.0 s later. What is the acceleration of the motorcycle (in meters/second^2)?

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To find the acceleration of the motorcycle, we need to determine the change in velocity and the time it took for the motorcycle to change its velocity.

First, let's convert the velocities from km/hr to m/s:
- The motorcycle's velocity is 91.0 km/hr, which is (91.0 * 1000) / (60 * 60) = 25.28 m/s.
- The car's velocity is 83.0 km/hr, which is (83.0 * 1000) / (60 * 60) = 23.06 m/s.

Next, let's determine the initial separation between the motorcycle and the car:
- The motorcycle is 52.0 m behind the car.

To calculate the change in velocity, we subtract the initial velocity of the motorcycle from the final velocity of the motorcycle:
- Change in velocity = Final velocity of the motorcycle - Initial velocity of the motorcycle.

The final velocity of the motorcycle is the same as its initial velocity since it is moving at a constant speed after passing the car, so:
- Change in velocity = 25.28 m/s - 25.28 m/s = 0 m/s.

Now, let's determine the time it took for the motorcycle to change its velocity by passing the car:
- The time is given as 16.0 s.

Finally, we can calculate the acceleration of the motorcycle using the equation:
- Acceleration = Change in velocity / Time taken.

Plugging in the values we found:
- Acceleration = 0 m/s / 16.0 s = 0 m/s^2.

Therefore, the acceleration of the motorcycle is 0 m/s^2.