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October 21, 2014

October 21, 2014

Posted by **jholm** on Tuesday, January 31, 2012 at 6:21pm.

- physics -
**drwls**, Tuesday, January 31, 2012 at 8:42pmLet that distance be H.

Time to reach top of window:

t1 = sqrt(2 H/g)

Time to reach bottom of window:

t2 = sqrt([2(H+2.3)/g]

t2 - t1 = 0.32 = sqrt[2(H+2.3)/g] -sqrt(2H/g)

g = 9.8 m/s^2. You have only one unknown. Solve for H

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