A falling stone takes 0.320 s to pass a window 2.30 m high. From what height (in meters) above the top of the window did the stone fall?

Let that distance be H.

Time to reach top of window:
t1 = sqrt(2 H/g)

Time to reach bottom of window:
t2 = sqrt([2(H+2.3)/g]
t2 - t1 = 0.32 = sqrt[2(H+2.3)/g] -sqrt(2H/g)

g = 9.8 m/s^2. You have only one unknown. Solve for H

.789m/s^2

To find the height from which the stone fell, we can use the equation for free fall motion.

The formula for the height (h) from which an object falls can be calculated using the equation: h = (1/2) * g * t^2

Where:
h is the height
g is the acceleration due to gravity (approximately 9.8 m/s^2)
t is the time taken for the object to fall

In this case, the stone took 0.320 seconds to pass a window 2.30 meters high. We need to find the height from which the stone fell.

Let's plug in the values into the equation:

h = (1/2) * g * t^2
= (1/2) * 9.8 m/s^2 * (0.320 s)^2
= 0.5 * 9.8 m/s^2 * 0.1024 s^2
≈ 0.5 * 1.01 m
≈ 0.505 m

Therefore, the stone fell from a height of approximately 0.505 meters above the top of the window.