Posted by jholm on Tuesday, January 31, 2012 at 6:21pm.
Let that distance be H.
Time to reach top of window:
t1 = sqrt(2 H/g)
Time to reach bottom of window:
t2 = sqrt([2(H+2.3)/g]
t2 - t1 = 0.32 = sqrt[2(H+2.3)/g] -sqrt(2H/g)
g = 9.8 m/s^2. You have only one unknown. Solve for H
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