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March 25, 2017

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If someone kicks a soccer ball across a flat parking lot with an initial velocity of 19.0m/s @ 19 degrees, how long will the soccer ball be in flight and how high above its launch point will the ball go? What would be the x and y components of this velocity at t=0.

  • physics - ,

    Vo = 19m/s @ 19 Deg.
    Xo = 19*cos19 = 17.96 m/s.
    Yo = 19*sin19 = 6.19 m/s.

    Tr = (Yf-Yo)/g,
    Tr = (0-6.19) / -9.8 = 0.63 s. = Rise time.

    a. Tf = Tr = 0.63 s.
    Tr + Tf = 0.63 + 0.63 = 1.26 s. = Time
    in flight.

    b. h = (Yf^2-Yo^2)/2g,
    h = (0-(6.19)^2) / -19.6 = 1.95 m.

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