algebra
posted by teesha .
a woodworking project calls for three pieces. the longest piece is twicw the length of the middlesized piece, and the shortest is 10 inches shorther than the middlesized piece. the board os 70 inches. how much must each peice be?

Let the middlesized piece be x.
Then: 2x = longest piece and x10 = shortest piece.
Therefore:
x + 2x + x  10 = 70
Can you take it from here?
(Hint: solve for x, then be sure to list the length of the 3 pieces!) 
SOLUTION: If the middle of three consecutive even integers is added to 100, the result is 42 more than the sum of the largest and twice the smallest. Find the smallest integer

20