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Posted by on Tuesday, January 31, 2012 at 11:05am.

2y^2 -8y -3 = 0
please solve

  • Math - , Tuesday, January 31, 2012 at 8:37pm

    Since this equation does not factor easily, use the quadratic formula to solve for x.

    x = [-b + or - √(b^2 - 4ac)]/2a

    a = 2, b = -8, and c = -3

    Substitute the values and solve for x.

    I'll let you take it from here.

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