posted by Amir on .
2y^2 -8y -3 = 0
Since this equation does not factor easily, use the quadratic formula to solve for x.
x = [-b + or - √(b^2 - 4ac)]/2a
a = 2, b = -8, and c = -3
Substitute the values and solve for x.
I'll let you take it from here.