college algebra
posted by Betty .
Please show me how to work this
e^.05t =1600

log = natural logarithm
log ( a ^ n ) = n * log ( a )
If your expression mean :
e ^ ( 0.05 t ) = 1600
then :
0.05 t * log ( e ) = log ( 1600 )
Remark : The natural logarithm of e = 1
0.05 t = log ( 1600 ) Divide both sides by 0.05
t = log ( 1600 ) / 0.05
Remark : 1 / 0.05 = 20
t = 20 * log ( 1600 )
t = 20 * 7.3777589
t = 147.555178