If 72% of Americans have straight hair, 76% have brown eyes, 87% are high school graduates, and 88% are less than 6 feet tall, what is the minimum percentage of Americans who have all four attributes?
I came up with 23%. Correct?
To find the minimum percentage of Americans who have all four attributes, we need to determine the largest overlap between these percentages. This can be done by multiplying the percentages together.
First, let's find the overlap between the percentages for straight hair and brown eyes. Multiply 72% and 76%:
(72/100) * (76/100) = 0.72 * 0.76 = 0.5472
So the overlap between straight hair and brown eyes is approximately 54.72%.
Next, find the overlap between this result and the percentage for being a high school graduate. Multiply the result obtained above (54.72%) and 87%:
0.5472 * (87/100) = 0.5472 * 0.87 = 0.4752864
The overlap between straight hair, brown eyes, and being a high school graduate is approximately 47.53%.
Finally, find the overlap between this result and the percentage for being less than 6 feet tall. Multiply the result obtained above (47.53%) and 88%:
0.4752864 * (88/100) = 0.4752864 * 0.88 = 0.418236032
The overlap between straight hair, brown eyes, being a high school graduate, and being less than 6 feet tall is approximately 41.82%.
Therefore, the minimum percentage of Americans who have all four attributes is approximately 41.82%.