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A charged particle of mass 6.38x10^-31kg is suspended motionless in the air by an electric field. If the electric field is 7.52x10^-21 N/C downwards, what is the magnitude and sign of the charge of
the particle?

  • Physics -

    Require than m * g = q * E

    q is the charge. m is the mass in kg.
    g is the acceleration of gravity, in m/s^2.
    E is the field strength, in N/C
    Solve for the field, charge, q, in Coulombs.

    The charge must be negative so that the upward electrical force can balance the weight.

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