Posted by **Anonymous** on Monday, January 30, 2012 at 6:18pm.

A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 128 feet per second. Its height in feet at t seconds is f(t)=16t^2+128t. Find the time its hits the ground and the time it reaches its highest point.

- Calculus -
**Reiny**, Monday, January 30, 2012 at 6:29pm
Your equation should be

f(t) = - 16t^2 + 128t

so

-16t^2 + 128t = 0

t^2 - 8t = 0

t(t-8) = 0

t = 0 ----> when you tossed it

t = 8 ----> when it lands

so it reached the hightest point at the midpoint of that 8 seconds, namely at 4 seconds

f(4) = -16(4^2) + 128(4)

= 256 ft

Wow!, That is quite a feat to through a pomegranate 256 feet into the air!!!!!

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