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March 25, 2017

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A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 128 feet per second. Its height in feet at t seconds is f(t)=16t^2+128t. Find the time its hits the ground and the time it reaches its highest point.

  • Calculus - ,

    Your equation should be
    f(t) = - 16t^2 + 128t

    so
    -16t^2 + 128t = 0
    t^2 - 8t = 0
    t(t-8) = 0
    t = 0 ----> when you tossed it
    t = 8 ----> when it lands

    so it reached the hightest point at the midpoint of that 8 seconds, namely at 4 seconds
    f(4) = -16(4^2) + 128(4)
    = 256 ft

    Wow!, That is quite a feat to through a pomegranate 256 feet into the air!!!!!

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