Posted by **Anonymous** on Monday, January 30, 2012 at 6:18pm.

A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 128 feet per second. Its height in feet at t seconds is f(t)=16t^2+128t. Find the time its hits the ground and the time it reaches its highest point.

- Calculus -
**Reiny**, Monday, January 30, 2012 at 6:29pm
Your equation should be

f(t) = - 16t^2 + 128t

so

-16t^2 + 128t = 0

t^2 - 8t = 0

t(t-8) = 0

t = 0 ----> when you tossed it

t = 8 ----> when it lands

so it reached the hightest point at the midpoint of that 8 seconds, namely at 4 seconds

f(4) = -16(4^2) + 128(4)

= 256 ft

Wow!, That is quite a feat to through a pomegranate 256 feet into the air!!!!!

## Answer this Question

## Related Questions

- Pre-Calculus - A pomegranate is thrown from a ground level straight up into the ...
- Math - Two kids are building a rocket for science class. once the rocket is ...
- math/physics - A pomegranate is thrown from ground level straight up into the ...
- math - An object that is falling or vertically projected into the air has it ...
- Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...
- Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...
- math - using this information: if an object is thrown straight up into the air ...
- math - using this information: if an object is thrown straight up into the air ...
- calculus - A ball is thrown vertically upward with an initial velocity of 128 ...
- math. can someone explain this! - using this information: if an object is thrown...

More Related Questions