log(base2)x-log(base2)6= log(base2)5+ 2log(base2)3

log(x/6)=3log15

(x/6)=15^3

6*(x/6)=15^3*6

x=15^3*6
=20,250

Answer is 270....

What did I do wrong...

2log(base2)3 is the same as log(base2)3^2, which would be log(base2)9.

Therefore, we have:

log(x/6) = log45

x/6 = 45

x = 45 * 6 = 270