Posted by Anne on Monday, January 30, 2012 at 4:49pm.
diagonal of the square = .25 * √(2)
√(2) is the square root of 2 (which equals 1.414)
corner A:
------------
k*q1/0.35 =(9*10^9)*(1.5*10^-9)/0.35 =38.6 V
k*q2/0.25 =(9*10^9)*(4*10^-9)/0.25 =144 V
then we add these to get the sum
38.6+144 = 182.6 V.
PE = q3 * (sum of V) = (-7.00*10^-9)* 182.6 = -1.2782*10^-6 J
Corner B:
-----------
k*q1/0.25 =(9*10^9)*(1.5*10^-9)/0.25 =54 V
k*q2/0.35 =(9*10^9)*(4*10^-9)/0.35 =102.9 V
then we add these to get the sum
54+102.9 = 156.9 V.
PE = q3 * (sum of V) = (-7.00*10^-9)* 156.9 = -1.0983*10^-6 J
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