Homework Help: college algebra

Posted by missy on Monday, January 30, 2012 at 2:34pm.

A model rocket is launches upward with an initial velocity of 160 feet per second. The height, in feet, of the rocket t seconds after the launch is given by h=-16t^2+160t. How many seconds after the launch will the rocket be 290 feet above the ground? Round to the nearest tenth of a second.

college algebra - Reiny, Monday, January 30, 2012 at 3:03pm
solve
290 = -16t^2 + 160t
16t^2 - 160t + 290 = 0

I don't think it factors, so use the formula to solve

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