Posted by **how to do this?** on Monday, January 30, 2012 at 1:11pm.

a pendulum with a length of .600 m has a period of 1.55 s. what is acceleration due to gravity at the pendulums location

- physics -
**Damon**, Monday, January 30, 2012 at 4:24pm
potential energy = m g h = m g L (1-cosA)

if angle A is small, cos A = 1 - A^2/2 +...

so

Pe = m g L A^2/2

kinetic energy = (1/2) m v^2 = (1/2) m L^2 [dA/dt]^2)

if A = sin wt

dA/dt = -w cos wt

max potential energy at top = max Ke at bottom

(1/2) m L^2 w^2 = (1/2) m g L

w^2 = g/L which by the way is in your book

g = L w^2

but w = 2 pi /T since when t = T, the angle w t must be 2 pi, full circle

g = L (2 pi)^2 / T^2

here L = .6 and T = 1.55

so g = 9.85 m/s^2

## Answer this Question

## Related Questions

- physics - calculate the period and frequency of a 3.500 m long pendulum at the ...
- physics - The acceleration due to gravity on the moon is 1.62 m/s2. What is the ...
- physics - The acceleration due to gravity on the moon is 1.62 m/s2. What is the ...
- physics - The acceleration due to gravity on the moon is 1.62 m/s2. What is the ...
- physics - When a pendulum with a period of 2.00000 s is moved to a new location ...
- Physics - Two physical pendulums (not simple pendulums) are made from meter ...
- physics - Suppose a simple pendulum is used to measure the acceleration due to ...
- physics - A pendulum clock can be approximated as a simple pendulum of length 1....
- PHYSICS - A physical pendulum consists of a disc of radius R and mass m fixed at...
- PHYSICS - A physical pendulum consists of a disc of radius R and mass m fixed at...