Posted by **help-not sure how to do this** on Monday, January 30, 2012 at 12:51pm.

A Spring (k=790 N/m) has a length of 48 cm when zero net force is applied to it. What will its length be when 230 N of force is applied to stretch it?

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**drwls**, Monday, January 30, 2012 at 12:59pm
Divide the force (230 N) but the spring constant k (790 N/m), and you will get the increase in length. You should get 0.3026 m, which is 30.26 cm.

Add that to the original length to get the new spring length with that force applied. m. Assume that the spring is being stretched. (It could also be compressed, in which case you would subtract the 30.36 m)

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**any**, Thursday, October 11, 2012 at 2:40am
this one is messed up

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**Anonymous**, Saturday, October 24, 2015 at 3:10am
123

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**Anonymous**, Wednesday, March 30, 2016 at 3:14pm
230 divided by 790

= .29113924m

= .291m

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