PHYSICS
posted by Rebecca on .
A water pistol aimed horizontally projects a stream of water with an initial speed of 5.00 m/s.
(a) How far does the water drop in moving 1.00 m hori
zontally?
(b) How far does it travel before dropping a vertical
distance of 1.00 cm?

(a) It takes
t = 1.00/5.00 = 0.2 seconds
to travel 1.0 meter horizontally.
Use the formula
(elevation change) = (g/2) t^2
(b) To fall 1.00 cm, the time required is
given by
0.01 = (g/2) t^2
t = 0.0452 s
The horizontal distance traveled by the water in that time is
5*0.0452 meters 
.2 seconds
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