A force of 1000 N is applied to a 1200 kg car. If the coefficient of friction is 0.04, what is the car's acceleration?
a = Fnet/m
The net force is
Fnet = 1000 - M*g*Uk
= 1000 - 470.4 = 529.6 N
a = 529.6/1200 = 0.441 m/s^2
how did you cope in this answer what is the formula and solution?
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To find the car's acceleration, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = m * a).
In this case, we are given the force (F) applied to the car, which is 1000 N, and the mass (m) of the car, which is 1200 kg. The coefficient of friction (µ) is also given, which is 0.04.
The force acting on the car can be broken down into two components: the force of friction (Ff) and the force causing acceleration (Fa). The force of friction can be calculated using the equation Ff = µ * N, where N is the normal force, which is the force exerted by the ground on the car. In this case, the normal force is equal to the weight of the car, which is mass multiplied by the acceleration due to gravity (N = m * g).
Since we are not given any information about inclined surfaces or acceleration due to gravity, we will assume it is on a level surface, and we will use the standard value for acceleration due to gravity, which is approximately 9.8 m/s^2.
The weight of the car can be calculated using the equation W = m * g, where W represents the weight.
Now, let's find the force of friction:
Ff = µ * N
N = m * g
Ff = µ * (m * g)
Substituting in the values given:
Ff = 0.04 * (1200 kg * 9.8 m/s^2)
Ff = 0.04 * 11760 N
Ff = 470.4 N
Now, let's find the force causing acceleration (Fa):
Fa = F - Ff
Fa = 1000 N - 470.4 N
Fa = 529.6 N
Finally, we can use Newton's second law to find the acceleration:
F = m * a
529.6 N = 1200 kg * a
Dividing both sides by 1200 kg:
a = 529.6 N / 1200 kg
a ≈ 0.441 m/s^2
Therefore, the car's acceleration is approximately 0.441 m/s^2.