A force of 1000 N is applied to a 1200 kg car. If the coefficient of friction is 0.04, what is the car's acceleration?
Physics - drwls, Monday, January 30, 2012 at 6:56am
a = Fnet/m
The net force is
Fnet = 1000 - M*g*Uk
= 1000 - 470.4 = 529.6 N
a = 529.6/1200 = 0.441 m/s^2
Physics - Maria Ellah, Monday, January 30, 2012 at 7:05am
Physics - jocynt, Wednesday, May 20, 2015 at 10:49am
how did you cope in this answer what is the formula and solution?