Physics
posted by Maria Ellah on .
A force of 1000 N is applied to a 1200 kg car. If the coefficient of friction is 0.04, what is the car's acceleration?

a = Fnet/m
The net force is
Fnet = 1000  M*g*Uk
= 1000  470.4 = 529.6 N
a = 529.6/1200 = 0.441 m/s^2 
thank you!

how did you cope in this answer what is the formula and solution?