Homework Help: PHYSICS

Posted by Anonymous on Monday, January 30, 2012 at 1:03am.

A ball is thrown from a point 1.1 m above the ground. The initial velocity is 20.3 m/s at an angle of 32.0° above the horizontal.

(a) Find the maximum height of the ball above the ground???

(b) Calculate the speed of the ball at the highest point in the trajectory???

PHYSICS - Henry, Tuesday, January 31, 2012 at 8:27pm
Vo = 20.3 m/s @ 32 Deg.
Xo = 20.3*cos32 = 17.2 m/s.
Yo = 20.3*sin32 = 10.76 m/s.

a. hmax = 1.1 + (Yf^2-Yo^2/2g,
hmax=1.1 + (0-(10.76)^2) / -19.6=7.0 m.

b. Yf = 0 @ hmax.

Answer this Question

Related Questions

Physics - A ball is thrown from a point 1.1 m above the ground. The initial ...
PHYSICS - A ball is thrown from a point 1.1 m above the ground. The initial ...
PHYSICS - A ball is thrown from a point 1.2 m above the ground. The initial ...
physics - A ball is thrown from a point 1.38 m above the ground. The initial ...
Physics - A ball is thrown from a point 1.38 m above the ground. The initial ...
Physics - A ball is thrown from a point 1.38 m above the ground. The initial ...
Physics - A ball is thrown from a point 1.0 m above the ground. The initial ...
Physics - A ball is thrown from a point 1.38 m above the ground. The initial ...
Physics - A ball is thrown towards a vertical wall from a point 2m above the ...
Physics - A 0.2 kg baseball located at the top of a building which is 100 m ...

For Further Reading

First Name:
School Subject:
Answer: