Posted by **ali** on Monday, January 30, 2012 at 12:22am.

A quarterback throws a football with a velocity vo at an angle of 45o with the horizontal. At the same instant a receiver standing 20 ft in front starts running down the field at 15 ft/s and catches the ball. What is the distance of the receiver from the quarterback when the ball is caught. Assume the ball is thrown and caught at the same height above the ground.

- Dynamics -
**drwls**, Monday, January 30, 2012 at 2:35am
distance ball thrown = receiver's distance from QB when caught

[2 vo sin 45/g]*vr + 20 = vo^2/g

vr = runner's velocity = 15 ft/s

g = 32.2 ft/s^2

You have one unknown, vo. Solve for it (using the quadratic formula) and use the answer to compute the distance thrown, vo^2/g.

## Answer this Question

## Related Questions

- Physics - A quarterback throws a football toward a receiver with an initial ...
- physics - A quarterback throws a football toward a receiver with an initial ...
- physics - A quarterback throws a football toward a receiver with an initial ...
- Physics - A quarterback throws a football toward a receiver with an initial ...
- Physic - A quarterback (QB) is running at 3.2 m/s at an angle of 25 degrees ...
- physics - A quarterback throws the football to a stationary receiver who is 18.3...
- Physics - A quarterback is trying to throw a football to a stationary receiver. ...
- physics - A quarterback throws the football to a stationary receiver who is 22....
- Physics - A quarterback throws a football toward a receiver with an initial ...
- physics - A quarterback throws the football to a stationary receiver who is 22.7...

More Related Questions