Posted by Jake on Sunday, January 29, 2012 at 11:39pm.
Evaluate log(Base4) ^3sqrt64 (The ^3 is an exponent infront of sqrt 64)
I keep getting wrong answer :

Precalculus  Jai, Sunday, January 29, 2012 at 11:57pm
ahh i think you mean cube root for that ^3sqrt(64). if so,
log(base4) of (cuberoot(64))
note that we can rewrite cuberoot(64) as cuberoot(4^3) which is equal 4.
log(base4) of 4 = 1
hope this helps~ :)

Precalculus  Jake, Monday, January 30, 2012 at 12:09am
If the base was 2 then it would be cuberoot 2^6?

Precalculus  Jai, Monday, January 30, 2012 at 12:59am
yes.

Precalculus  Damon, Monday, January 30, 2012 at 3:22am
log4 (64)^(1/3)
(1/3) log4 (64)
but log 4(64) = log4(4^3)
so
(1/3)(3) log4(4)
but log4(4) = 1
so
answer = 1
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