Posted by **Jake** on Sunday, January 29, 2012 at 11:39pm.

Evaluate log(Base4) ^3sqrt64 (The ^3 is an exponent infront of sqrt 64)

I keep getting wrong answer :|

- Precalculus -
**Jai**, Sunday, January 29, 2012 at 11:57pm
ahh i think you mean cube root for that ^3sqrt(64). if so,

log(base4) of (cuberoot(64))

note that we can rewrite cuberoot(64) as cuberoot(4^3) which is equal 4.

log(base4) of 4 = 1

hope this helps~ :)

- Precalculus -
**Jake**, Monday, January 30, 2012 at 12:09am
If the base was 2 then it would be cuberoot 2^6?

- Precalculus -
**Jai**, Monday, January 30, 2012 at 12:59am
yes.

- Precalculus -
**Damon**, Monday, January 30, 2012 at 3:22am
log4 (64)^(1/3)

(1/3) log4 (64)

but log 4(64) = log4(4^3)

so

(1/3)(3) log4(4)

but log4(4) = 1

so

answer = 1

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