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Precalculus

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Evaluate log(Base4) ^3sqrt64 (The ^3 is an exponent infront of sqrt 64)

I keep getting wrong answer :|

  • Precalculus - ,

    ahh i think you mean cube root for that ^3sqrt(64). if so,
    log(base4) of (cuberoot(64))
    note that we can rewrite cuberoot(64) as cuberoot(4^3) which is equal 4.
    log(base4) of 4 = 1

    hope this helps~ :)

  • Precalculus - ,

    If the base was 2 then it would be cuberoot 2^6?

  • Precalculus - ,

    yes.

  • Precalculus - ,

    log4 (64)^(1/3)

    (1/3) log4 (64)

    but log 4(64) = log4(4^3)
    so
    (1/3)(3) log4(4)
    but log4(4) = 1
    so
    answer = 1

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