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April 1, 2015

April 1, 2015

Posted by **Steven** on Sunday, January 29, 2012 at 11:31pm.

(2x^(-3)y^(2))^(-2)

and

(z^4)/(2z^3)

Thanks!

- Algebra II -
**Jai**, Sunday, January 29, 2012 at 11:49pm#1

(2x^(-3)y^(2))^(-2)

(2)^(-2) * x^(-3*(-2)) * y^(2*(-2))

(1/4) * x^(6) * (1/y^4)

(x^6)/(4y^4)

#2

(z^4)/(2z^3)

z/2

hope this helps~ :)

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