Posted by kaf on Sunday, January 29, 2012 at 10:51pm.
At time t after throwing,
Y (measured from the ground) = H + 16sin40*t - 4.9 t^2
H is the building height.
Set Y = 0 at t = 3.4s and solve for H
H = 0 + 4.9*(3.6)^2 - 34.97 = 28.53 m
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