posted by kyle on .
A ball is dropped from the top of a 95 m building. With what speed does the ball hit the ground?
The kinetic energy when it hits the ground equals the initial potential energy.
M*g*H = (1/2)MV^2
V = sqrt(2 g H)
H is the initial height and g is the acceleration of gravity.
Aerodynamic friction has been neglected. The true velocity will be slightly less