Posted by **amanda and leah** on Sunday, January 29, 2012 at 9:18pm.

A(n) 5.52 g bullet is fired into a(n) 3.07 kg ballistic pendulum and becomes embedded in it.The acceleration of gravity is 9.8 m/s^2. If the pendulum rises a vertical distance of 4.48 cm, calculate the initial speed of the bullet. Answer in units of m/s

- Physics -
**drwls**, Sunday, January 29, 2012 at 9:36pm
Apply conservation of energy during the upward swing to compute the velocity of the pendulm with imbedded bullet.

V= sqrt(2gH)= 0.937 m/s

Then apply conservatuion of momentum to the bullet-imbedding process to compute the initial velocity of the bullet, v.

v*m = (M+m)V

m = bullet mass.

M = pendulum mass

Solve for v.

## Answer This Question

## Related Questions

- physics - A(n) 3.46 g bullet is fired into a(n) 2.4 kg ballistic pendulum and ...
- mambane - A 10.0g bullet is fired with a speed of 500m/s into a pendulum block ...
- physic - A 25 gm bullet is fired into a 2.25kg ballistic pendulum and becomes ...
- physic - A 25 gm bullet is fired into a 2.25kg ballistic pendulum and becomes ...
- Physic - A 25 gm bullet is fired into a 2.25kg ballistic pendulum and becomes ...
- Physics - A bullet of mass 3.2 g strikes a ballistic pendulum of mass 3.6 kg. ...
- physics - A bullet of mass 8 g strikes a ballistic pendulum of mass 2.0 kg. The ...
- physics for physical science - a bullet of mass 0.015kg strikes ballistic ...
- Physics - A bullet of mass 4.8 g strikes a ballistic pendulum of mass 3.3 kg. ...
- physics - A ballistic pendulum consists of a rectangular wooden block of mass 1....

More Related Questions