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December 10, 2016
Posted by **Melinda** on Sunday, January 29, 2012 at 8:52pm.

Two identities are: sin^2x + cos^2x = 1 and tan2x=2tanx/1-tan^2x

- Precalculus -
**Reiny**, Sunday, January 29, 2012 at 9:49pmyour are correct

2tanx/(sin^2x + cos^2x - tan^2x)

= 2tanx/(1 - tan^2 x)

= tan(2x) - Precalculus -
**Melinda**, Sunday, January 29, 2012 at 10:01pmThank you~