engineering
posted by Anonymous on .
an airplane was moving with a velocity equal to 300 mph when the velocity was increased with uniform acceleration to 600 mph in 5 min. calculate the number of miles the airplane traveled during that interval of time

Vo = 300mi/h * 1600m/mi * 1h/3600s =133.3 m/s.
Vf = (600/300) * 133.33 = 266.66 m/s.
t = 5min * 60s/min = 300 s.
a = (VfVo)/t = (266.66133.33) / 300 =
0.444 m/s^2.
d = Vo*t + 0.5a*t^2,
d = 133.33*300 + 0.222*(300)^2=59,979 m
= 37.5 mi.