Wednesday

April 1, 2015

April 1, 2015

Posted by **Anonymous** on Sunday, January 29, 2012 at 4:52pm.

velocity whose magnitude is 5fps. A second car, on the same track, that

weighs 40,000 lbs also traveling in an easterly direction with a

velocity of 7.8fps. When the cars collided, they became coupled together

and then both cars moved with the same velocity. If friction between the

cars and the rails is neglected, what were the magnitude and the

direction of the velocity of the car after the collision?

- mechanical engineering -
**Damon**, Sunday, January 29, 2012 at 5:05pmMomentum before = m1 v1 + m 2 v2

Momentum after = (m1+m2) v

then

momentum after = momentum before.

**Answer this Question**

**Related Questions**

Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...

Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...

Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...

Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...

Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides ...

Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides in ...

Physics - A 40,000 kg railroad car initially traveling at 10 m/s collides in ...

Physics - A two head collision. One car weighs 45000 newtons and going at 15 ...

Physical Science - A 20,000 kg railroad car is traveling at 3 m/s when it ...

college physics - A(n) 13,300 lb railroad car traveling at 7.4 ft/s couples with...