algebra
posted by bob on .
parking lot had a length that is 7 yards greater than thre width. the area of the lot is 450 square yards. what is the length and width?

x(x+7) = 450
x^2 + 7 x  450 = 0
x = [  7 +/ sqrt (49+1800) ] / 2
x = [  7 +/ sqrt (1849) ] / 2
x = [ 7 +/ 43 ]/2
x = 18
x+7 = 25