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March 30, 2017

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A 20.0kg curling stone at the hog line and moves 28.35m [west] to sit on the button and score a point. If the coefficient of kinetic friction between the stone and the ice is 0.00200, what was the initial speed of the stone when it was released?

  • Physics - ,

    F = - 20 * 9.8 * .002
    F = m a
    -20 * 9.8 * .002 = 20 a
    a = -19.6 *10^-3 m/s^2

    stops at time t at the button
    v = Vi + a t
    0 = Vi + a t
    t = -Vi/a

    d = Vi t + (1/2) a t^2
    28.35 = Vi (-Vi/a) + (a/2) Vi^2/a^2
    28.35 = -Vi^2/a + (1/2) Vi^2/a
    28.35 = -(1/2) Vi^2/a
    so
    Vi^2 = -2 (28.35)(-19.6*10^-3)
    Vi^2 = 1111
    Vi = 33.3 m/s

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