Post a New Question
posted by chelsea on Sunday, January 29, 2012 at 2:49pm.
give exact and approximate to three decimals places x^2+8x+16=25 Please help me solve this
x^2+8x+16-25 = 0, x^2+8x-9 = 0, (x+9(x-1) = 0, x+9 = 0, X = -9. x-1 = 0, X = 1. Solution set: X = -9, and X = 1.
More Related Questions