admission to a park is $5 for an adult ticket and $1 for a child. If $100 was collected and 28 admissions were sold on a day, how many tickets were sold and how many child tickets were sold
Let x = adult and Y = child tickets.
x + y = 28
x = 28 - y
5x + y = 100
Substitute 28-y for x in third equation and solve for y. Insert that value into the first equation and solve for x. Check by inserting both values into the third equation.
from a board 38 1/2 inches long pete cut a piece 17 5/8 inches long how long was the remaining piece
To solve this problem, we'll need to set up a system of equations and solve them simultaneously.
Let's assume the number of adult tickets sold is "x" and the number of child tickets sold is "y".
From the given information, we know that the total amount collected from ticket sales is $100, and the total number of admissions sold is 28. Therefore, we can set up the following two equations:
1. x + y = 28 (equation representing the number of admissions sold)
2. 5x + 1y = 100 (equation representing the total amount collected)
Now we can solve the system.
To do this, we can use the method of substitution.
From equation 1, we can solve it for x:
x = 28 - y
Now we substitute this value of x into equation 2:
5(28 - y) + 1y = 100
Simplifying the equation:
140 - 5y + y = 100
-4y = -40
y = 10
Substituting the value of y back into equation 1 to find x:
x + 10 = 28
x = 28 - 10
x = 18
Therefore, 18 adult tickets and 10 child tickets were sold.
To summarize:
Number of adult tickets sold: 18
Number of child tickets sold: 10