1) Which one of the following molecules is the most polarizable?

a) H3C – I b) H3C – CH3
c) H3C – F

d) H3C – H e) H3C – OH

I chose H3C-I as the answer because the mm was the greatest. I added the mm of H, C, and I and got 141.934. Did I do this correctly?

To determine which molecule is the most polarizable, you need to consider the electronegativity difference between the atoms in each molecule.

Electronegativity is the measure of an atom's ability to attract electrons towards itself in a chemical bond. The greater the electronegativity difference between two atoms, the more polar the bond, and hence the more polarizable the molecule.

In this case, the electronegativity values of the elements are as follows:

H = 2.20
C = 2.55
F = 3.98
I = 2.66
O = 3.44

To predict the polarizability, you need to focus on the difference between the electronegativity values of the central atom and the surrounding atoms. The larger the electronegativity difference, the more polarizable the molecule.

Let's go through the options:
a) H3C-I: The electronegativity difference is |2.66 - 2.20| = 0.46
b) H3C-CH3: There is no significant electronegativity difference as both carbon and hydrogen have similar electronegativity values.
c) H3C-F: The electronegativity difference is |3.98 - 2.20| = 1.78
d) H3C-H: There is no significant electronegativity difference as both carbon and hydrogen have similar electronegativity values.
e) H3C-OH: The electronegativity difference is |3.44 - 2.20| = 1.24

From the given options, the molecule with the largest electronegativity difference, and thus the most polarizable, is H3C-F.

Therefore, your answer, H3C-F, is correct. Please note that determining polarizability solely based on molar mass is not accurate since it does not consider the electronegativity differences between atoms.