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A water pistol aimed horizontally projects a stream of water with an initial speed of 5.65 m/s. How far does it travel before dropping a vertical distance of 1.50 cm?

  • Physics -

    Multiply the horizontal speed component (which remains constant) by the time T that it takes the water to fall 1.50 cm.

    (g/2) T^2 = 0.015 m
    T = sqrt(0.03/g) = 0.0553 s

    X = 0.313 m not very far!

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