Posted by PDF on Saturday, January 28, 2012 at 10:54pm.
A rubber ball rebounds 3/5 of the height from which it falls. If it is initially dropped from a height of 30 ft. What total vertical distance does it travel before coming to rest?

Algebra  Reiny, Sunday, January 29, 2012 at 9:07am
Make a diagram
distance during first bounce  15 ft
distance during 2nd bounce  2(15)(3/5)
distance during 3rd bounce = 2(15)(3/5)^2
distance during 4th bounce = 2(15)(3/5)^3
etc
from the 2nd term on, we have a geometric series
where a = 2(15)(3/5) = 18 and r = 3/5
and the want Sum∞
sum∞ = 15 + a/(1r)
= 15 + 18/(13/5)
= 15 + 18/(2/5)
= 15 + 45 = 60

Algebra  Abel, Friday, September 21, 2012 at 8:50am
a sub 1 = 30
r = 3/5
S = (r) / (1r)
S = {(30ft) / [(1)(3/5)]}(3/5)
S = 150ft / 53 = 150ft / 2 = 70ft

Algebra  Michelle, Monday, November 24, 2014 at 7:52pm
60

Algebra  Myla, Friday, January 8, 2016 at 1:16am
120 ft

Algebra  Anonymous, Thursday, July 7, 2016 at 12:43am
120...
30+ summation(X to infinity)(30*2*(3/5)^x)
30+90=120

Algebra  anonymous, Tuesday, November 22, 2016 at 7:53am
S = 30 + 2 [15/(13/5)]
S = 30 + 2(15/2/5)
S = 30 +75
S = 105 ft
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