Posted by **PDF** on Saturday, January 28, 2012 at 10:54pm.

A rubber ball rebounds 3/5 of the height from which it falls. If it is initially dropped from a height of 30 ft. What total vertical distance does it travel before coming to rest?

- Algebra -
**Reiny**, Sunday, January 29, 2012 at 9:07am
Make a diagram

distance during first bounce - 15 ft

distance during 2nd bounce - 2(15)(3/5)

distance during 3rd bounce = 2(15)(3/5)^2

distance during 4th bounce = 2(15)(3/5)^3

etc

from the 2nd term on, we have a geometric series

where a = 2(15)(3/5) = 18 and r = 3/5

and the want Sum∞

sum∞ = 15 + a/(1-r)

= 15 + 18/(1-3/5)

= 15 + 18/(2/5)

= 15 + 45 = 60

- Algebra -
**Abel**, Friday, September 21, 2012 at 8:50am
a sub 1 = 30

r = 3/5

S = (r) / (1-r)

S = {(30ft) / [(1)-(3/5)]}(3/5)

S = 150ft / 5-3 = 150ft / 2 = 70ft

- Algebra -
**Michelle**, Monday, November 24, 2014 at 7:52pm
60

- Algebra -
**Myla**, Friday, January 8, 2016 at 1:16am
120 ft

- Algebra -
**Anonymous**, Thursday, July 7, 2016 at 12:43am
120...

30+ summation(X to infinity)(30*2*(3/5)^x)

30+90=120

- Algebra -
**anonymous**, Tuesday, November 22, 2016 at 7:53am
S = 30 + 2 [15/(1-3/5)]

S = 30 + 2(15/2/5)

S = 30 +75

S = 105 ft

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