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August 29, 2014

August 29, 2014

Posted by **PDF** on Saturday, January 28, 2012 at 10:54pm.

- Algebra -
**Reiny**, Sunday, January 29, 2012 at 9:07amMake a diagram

distance during first bounce - 15 ft

distance during 2nd bounce - 2(15)(3/5)

distance during 3rd bounce = 2(15)(3/5)^2

distance during 4th bounce = 2(15)(3/5)^3

etc

from the 2nd term on, we have a geometric series

where a = 2(15)(3/5) = 18 and r = 3/5

and the want Sum∞

sum∞ = 15 + a/(1-r)

= 15 + 18/(1-3/5)

= 15 + 18/(2/5)

= 15 + 45 = 60

- Algebra -
**Abel**, Friday, September 21, 2012 at 8:50ama sub 1 = 30

r = 3/5

S = (r) / (1-r)

S = {(30ft) / [(1)-(3/5)]}(3/5)

S = 150ft / 5-3 = 150ft / 2 = 70ft

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