Posted by PDF on Saturday, January 28, 2012 at 10:54pm.
Make a diagram
distance during first bounce - 15 ft
distance during 2nd bounce - 2(15)(3/5)
distance during 3rd bounce = 2(15)(3/5)^2
distance during 4th bounce = 2(15)(3/5)^3
etc
from the 2nd term on, we have a geometric series
where a = 2(15)(3/5) = 18 and r = 3/5
and the want Sum∞
sum∞ = 15 + a/(1-r)
= 15 + 18/(1-3/5)
= 15 + 18/(2/5)
= 15 + 45 = 60
a sub 1 = 30
r = 3/5
S = (r) / (1-r)
S = {(30ft) / [(1)-(3/5)]}(3/5)
S = 150ft / 5-3 = 150ft / 2 = 70ft
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