Posted by Ken on Saturday, January 28, 2012 at 9:17pm.
Don't you mean the fulcrum was 36.75 cm from the end with the 200 g mass?
Or do you mean the center of mass of meterstick and both weights (together) is at 36.75 cm? That would also make sense.
Whether it is balanced or not depends upon where the fulcrum is.
The center of mass of the meter stick is probably at the 50 cm mark.
Set the total moment about the fulcrum equal to zero and solve for the mass of the meterstick.
The fulcrum is at 36.75
Set the total moment about the fulcrum equal to zero and solve for the mass M of the meterstick. (You can omit the g factors, which cancel out. I will leave mass in grams, and distances in cm).
200*36.75 + M*13.25 = 100*63.25
M = 79.23 g
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