Predict the reaction, if any, that would occur if Sr(NO3)2 and Na2CO3 were mixed. Would any reaction occur if HBr were added?
Thank You
Dry Sr(NO3)2 and dry Na2CO3 will not react. If aqueous solutions, yes.
Sr(NO3)2(aq) + Na2CO3(aq) ==> SrCO3(aq) + 2NaNO3(aq)
If HBr is added, carbonate reacts with H^+ to produce H2O(aq) and CO2(g)
To predict the reaction that would occur if Sr(NO3)2 and Na2CO3 were mixed, we need to determine if a reaction will take place by looking at the reactants.
Step 1: Write the chemical formulas for each reactant:
Sr(NO3)2 - strontium nitrate
Na2CO3 - sodium carbonate
Step 2: Identify the cations and anions in each reactant:
Sr(NO3)2 - cation: Sr2+, anion: NO3-
Na2CO3 - cation: Na+, anion: CO3^2-
Step 3: Determine if there is a possible reaction by comparing the cations and anions:
The cation Sr2+ and anion CO3^2- can form a precipitate because Na2CO3 is a soluble salt and most strontium compounds are insoluble. So, a reaction is likely to occur.
Step 4: Write the balanced chemical equation for the reaction:
Sr(NO3)2 + Na2CO3 → SrCO3 + 2NaNO3
This reaction forms strontium carbonate (SrCO3) and sodium nitrate (NaNO3) as the products.
Regarding the addition of HBr, we need to consider if any reaction would occur. HBr is a strong acid, so it can potentially react with certain compounds.
However, in this case, if we mix HBr with Sr(NO3)2 or Na2CO3, we do not expect any significant reaction to occur. HBr is a solution of hydrogen bromide, and it typically does not react with these specific compounds under normal conditions.
In summary, when Sr(NO3)2 and Na2CO3 are mixed, a reaction occurs to form strontium carbonate and sodium nitrate. Adding HBr to this mixture is not expected to cause any significant reaction.