Posted by **jackie** on Saturday, January 28, 2012 at 4:23pm.

A chemist is asked to make 10 liters of a a35% solution. She has only a 10% solution and a 50% solution to work with. how much of each solution must she mix to ge 10 liters of the 35% solution?

- ALGEBRA -
**AlanB.519691**, Saturday, April 4, 2015 at 12:06am
Using a double equation system;Let x be the 10% soln,so y is the 50% soln

Vol.Eqn1: x+y = 10L, then

Volx[conc]Eqn2:0.1x+0.5y= 0.35(10)

Eqn2-(Eqn1x0.5) gives xL

Therefore: 0.1x + 0.5y = 3.5

-0.5x + 0.5y = 5.0

-0.4x =-1.5

x = 1.5/0.4L= 3.75L

Therefore y is 10-3.75=6.25L of 50%soln

## Answer this Question

## Related Questions

- mixture problems - A chemist has two solutions of sulfuric acid. One is a 25% ...
- algebra - A laboratory assistant is asked to mix a 30% alcohol solution with 21 ...
- Math Algebra , high school - A biologist has three salt solutions: some 5% ...
- algebra - An industrial chemist will mix two acid solutions. One is 37% solution...
- algebra - a chemist needs 10 liters of a 25% acid solution. the solution is to ...
- Algebra - A chemist has one solution that is 80% acid and a second solution that...
- Chemistry - Captain Kirk, of the Starship Enterprise, has been told by his ...
- chemistry-confirm please - Only a chemist can be trusted with the combination to...
- Algebra - A chemist needs to mix a slution containing 30% insecticide with a ...
- math - A lab needs a 20 liters of a 15% acid solution. The lab only has a 10% ...

More Related Questions