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November 23, 2014

November 23, 2014

Posted by **Dave** on Saturday, January 28, 2012 at 3:31pm.

- Physics -
**Damon**, Saturday, January 28, 2012 at 3:55pmWell, I suppose I am to assume that you stopped in 108 meters.

first you went 12.7*.47 = 5.97 m before your foot hit the brake.

So the brakes must stop you in (108 -6) = 102 meters

That is the answer you asked for.

-----------------------------------

The rest of the problem:

102 = 12.7 t - (1/2) a t^2

and

0 = 12.7 - a t

t = 12.7/a

so

102 = 12.7^2/a - (1/2) (12.7^2)/a

204 a = 12.7^2

a = .8 m/s^2 about a tenth of g

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